Jump to content

Talk:Chapman–Robbins bound

Page contents not supported in other languages.
From Wikipedia, the free encyclopedia

Question: Is it important that θRn or it can be in arbitrary set ?

Answer: As far as I can tell, the proof works for arbitrary . But in order to be used for estimation theory, to make an estimator for , has to be -valued. And since is -valued in the theorem, it's better be in that context. — Preceding unsigned comment added by 77.179.139.65 (talk) 05:13, 9 August 2023 (UTC)[reply]